Exam FC0-U61 topic 1 question 92 discussion

Shouldn't this be ten? It says as Long as @count is LESS THAN 10, add 1. So when @count is equal to 10, It should stop. Because 10 is EQUAL TO 10. 10 is NOT LESS THAN 10

C. 10 Explanation: Let's go step by step through the pseudocode: declare @count int: Declares a variable @count of type int. set @count = 1: Initializes @count with the value of 1. for @count < 10: This starts a loop that will run as long as @count is less than 10. However, there's an issue with the pseudocode: it uses a for loop without a proper structure, but we can assume it's meant to be a while loop. begin: Starts the block of code inside the loop. set @count = @count + 1: Increases the value of @count by 1 in each iteration of the loop. end: Ends the loop. select @count: Outputs the final value of @count.

The answer is C. It would not print out 11 because the condition is LESS THAN not LESS THAN EQUAL TO

C is the correct answer, the code only loops if @count is under 10, once its value is 10, it stops looping, meaning the final output is 10. or C

Consider the following simple loop (python): count = 1 while count < 10: count += 1 print (count) that will print 10 in the console!

It's suppose to be 10. It enters loop for the final time at 9. Which sets it to 10. It can't run the loop after that since 10 is not less than 10. So it returns 10.

C. 10 for count =9: count < 10 count = 9+1 = 10 for count =10: loop does not enter count value ends with 10

@count=1. @count <10 @count= @count(1) + 10 So.. @count = 11

The loop is exited when count is 10

I believe it is 11 because when we look at the pseudo code, it has the +1 after the <10. This means that one more numbers adds up to the current one, therefore, it comes out as 10.

yes, it should be 10.

I agree, it should be 10