7 is correct. Assuming routers R1-R5, R1 is elected DR, R2 BDR. Fully established neighborships only occur to DR and BDR, all other neighbors are in 2Way DR other state. DR|BDRFull relationships:
R2-R1
R3-R1
R3-R2
R4-R1
R4-R2
R5-R1
R5-R2
The Scenario:
5 OSPF routers on a broadcast network.
DR and BDR are elected.
DROthers form adjacencies only with the DR and BDR.
Full Neighbor Relationships:
1) DR forms adjacencies with:
BDR (1 neighbor).
3 DROthers (3 neighbors).
Total: 4 adjacencies.
2) BDR forms adjacencies with:
DR (1 neighbor, counted already above).
3 DROthers (3 neighbors).
Total: 4 adjacencies.
3) DROthers form adjacencies with:
DR (1 adjacency each).
BDR (1 adjacency each).
No adjacencies with other DROthers.
**Total Neighbor Relationships:
Counting only unique, fully established adjacencies:
DR ↔ 4 (1 BDR + 3 DROthers).
BDR ↔ 4 (1 DR + 3 DROthers).
Total = 4 (DR) + 4 (BDR) − 1 (DR ↔ BDR counted twice) = 6.
wrong formula for OSPF in broadcast domain. Valid for IBGP full mesh though
upvoted 4 times
...
...
Log in to ExamTopics
Sign in:
Community vote distribution
A (35%)
C (25%)
B (20%)
Other
Most Voted
A voting comment increases the vote count for the chosen answer by one.
Upvoting a comment with a selected answer will also increase the vote count towards that answer by one.
So if you see a comment that you already agree with, you can upvote it instead of posting a new comment.
sat_be
Highly Voted 1 year, 7 months agoXalaGyan
6 months, 1 week agorockin
Most Recent 3 weeks, 5 days agoRim007
9 months, 1 week agoarumu_123
1 year, 7 months agoying162
1 year, 5 months ago