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Exam 350-401 topic 1 question 224 discussion

Actual exam question from Cisco's 350-401
Question #: 224
Topic #: 1
[All 350-401 Questions]

If the noise floor is -90 dBm and the wireless client is receiving a signal of גˆ’75 dBm, what is the SNR?

  • A. 15
  • B. 1.2
  • C. גˆ’165
  • D. .83
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Suggested Answer: A 🗳️

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Stylar
Highly Voted 2 years ago
Selected Answer: A
There is obviously a typo here, you cant go to the + range.. Maximum achievable strength is -30dbm. The question should say -75, not 75.
upvoted 10 times
kipson
1 day, 20 hours ago
The signal strength is typically a negative value, indicating a low power level. So, the correct signal strength is -75 dBm.
upvoted 1 times
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slacker_at_work
10 months, 2 weeks ago
For once you are making sense..
upvoted 1 times
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[Removed]
1 year, 5 months ago
This makes more sense.
upvoted 1 times
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Amoksepp
Highly Voted 1 year, 5 months ago
The correct answer is: E: run away because the radio waves reach your device with a power of 31622 W. :D
upvoted 7 times
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[Removed]
Most Recent 6 months, 2 weeks ago
Selected Answer: A
A is correct SNR = (-75 dBm) - (-90 dBm) = -75 dBm + 90 dBm = 15 dB https://documentation.meraki.com/MR/Wi-Fi_Basics_and_Best_Practices/Signal-to-Noise_Ratio_(SNR)_and_Wireless_Signal_Strength
upvoted 2 times
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Evreni
1 year, 1 month ago
Selected Answer: C
C: is correct https://www.omnicalculator.com/physics/signal-to-noise-ratio
upvoted 1 times
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Poba
1 year, 4 months ago
To calculate the Signal-to-Noise Ratio (SNR), we need to convert the signal and noise power from dBm to linear scale (watts) and then use the SNR equation: SNR (dB) = 10 * log10(signal power / noise power) Given: Noise floor = -90 dBm Signal strength = 75 dBm First, let's convert the signal and noise power to watts: Signal Power (W) = 10^((Signal Strength (dBm) - 30) / 10) Signal Power (W) = 10^((75 - 30) / 10) Signal Power (W) = 10^4.5 Signal Power (W) = 31,622.7766 W Noise Power (W) = 10^((Noise Floor (dBm) - 30) / 10) Noise Power (W) = 10^((-90 - 30) / 10) Noise Power (W) = 10^-12 Noise Power (W) = 0.000000000001 W Now, let's calculate the SNR in dB: SNR (dB) = 10 * log10(signal power / noise power) SNR (dB) = 10 * log10(31,622.7766 / 0.000000000001) SNR (dB) = 10 * log10(31,622,776,600,000,000) SNR (dB) = 10 * 16.5 SNR (dB) = 165 Therefore, the SNR is 165 dB. The correct answer is C.
upvoted 5 times
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danman32
1 year, 5 months ago
What is גˆ’ supposed to mean?
upvoted 4 times
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HungarianDish_111
1 year, 10 months ago
Selected Answer: A
The example might be taken from this site: https://documentation.meraki.com/MR/Wi-Fi_Basics_and_Best_Practices/Signal-to-Noise_Ratio_(SNR)_and_Wireless_Signal_Strength "For example, if a client device's radio receives a signal at -75 dBm, and the noise floor is -90 dBm, then the effective SNR is 15 dB. This would then reflect as a signal strength of 15 dB for this wireless connection. "
upvoted 3 times
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NJENI
1 year, 10 months ago
There is typo coz the the answer shud be 165
upvoted 2 times
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Typovy
2 years ago
Selected Answer: A
Asymptote is wrong, A is correct answer
upvoted 1 times
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Asymptote
2 years ago
Selected Answer: C
C SNR = signal strength in dBm - noise 75 - (-90) = 165 if a client device's radio receives a signal at -75 dBm, and the noise floor is -90 dBm, then the effective SNR is 15 dB. This would then reflect as a signal strength of 15 dB for this wireless connection. Reference: https://documentation.meraki.com/MR/Wi-Fi_Basics_and_Best_Practices/Signal-to-Noise_Ratio_(SNR)_and_Wireless_Signal_Strength#:~:text=if%20a%20client%20device%27s%20radio%20receives%20a%20signal%20at%20%2D75%20dBm%2C%20and%20the%20noise%20floor%20is%20%2D90%20dBm%2C%20then%20the%20effective%20SNR%20is%2015%20dB.%C2%A0This%20would%20then%20reflect%20as%20a%20signal%20strength%20of%2015%20dB%20for%20this%20wireless%20connection.%C2%A0
upvoted 2 times
dogdoglee
2 years ago
-75 -(-90) = 15
upvoted 7 times
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H3kerman
2 years, 2 months ago
Selected Answer: A
90-75=15
upvoted 1 times
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A (35%)
C (25%)
B (20%)
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