Exam 200-301 topic 1 question 488 discussion

A is 100% correct while the confusion between B and E is down to people missing two important differences for those two options. B is a direct host route and it will show up in the routing table as 10.10.10.10/32 and it is called a host route. Hence subnet mask being 255.255.255.255. Whereas, E option does NOT cover the host 10.10.10.10 address as if you calculate the subnet range for the subnet in option E it only goes up to 10.10.10.0 - 10.10.10.6 and .7 being its broadcast address. It's incrementing in blocks of 8 as the subnet mask clearly states 255.255.255.248 or /29. So, how exactly the router would send traffic to host .10 which is NOT even in the subnet range. Therefore, option E route will NEVER reach .10 host hanging off that router. Correct answer is A is the network route and B is direct host route, hope this helps :)

A and B

IP of PC5 must be .6 Then answers A and E are right

A & B are correct

only A is correct

A y B es la correcta

A and B

Anyone knows why C is wrong?

AB is correct. can't be E coz mask is not appropriate

10.10.10.0 255.255.255.248 Usable address range 10.10.10.1 to 10.10.10.6

AB is correct

A for sure but for our next answer is E Lets take a look at the other two posiible answer below: B )ip route 10.10.10.10 255.255.255.255 192.168.2.2 E) ip route 10.10.10.0 255.255.255.248 192.168.2.2 B tells the router it can only go to the 10.10.10.10 host. We can see that this is not a valid host. We are left with E. which if you do subletting can see you can reach each host that is configured. The problem with both B and E is that they are configure with the wrong next hop address for the intended network. We will relay on the router to route us over to the correct network

AB for sure

A & B is correct

This question is false. A is right, But none other one seems to be correct!

I almost punched my computer. Are they purposely trying give us wrong answers? A and B is the answer. E ranges from 10.10.10.0-10.10.10.7. 10.10.10.10 is out of the range.

a and b, the subnet of d does not exist