Refer to the exhibit. When an administrator executes the show ip route command on router D to view its routing table, which value is displayed for the administrative distance for the route to network 192.168 1.0?
A is correct because when EIGRP is redistributed the new AD will be 170 (external EIGRP) making OSPF the lowest AD available. Redistribution topic is in CCNP
Router A: advertises 192.168.1.0/24 using RIP v2(120)
Router B: Redistribute routes
Router D: receive from Router B using external EIGRP(170),
leaving with choice of OSPF(110) lowest AD
I have never covered route redistribution in any CCNA material I have covered through my course or on youtube. My first time hearing of this was through this question. I sincerely doubt this is CCNA level material
Router D will learn a route to 192.168.1.0 to from redistribution. It means the RIP route will be "translated" to EIGRP, and Router D will display it as external EIGRP route in the routing table.
When you run show ip route on Router D, the route will be shown as 'D EX' which means external EIGRP (AD = 170).
The correct answer is A because when routes are redistributed using default metrics. The routing protocols are re-assigned the metrics below:
RIP = Infinity
EIGRP = Infinity
OSPF = 20
This means that if default values are used to reconfigure redistribution. The AD value will be 110 and the metric will be 20.
Letter A is correct, it's simple:
If you test in Packet Tracer, you will see that every route redistributed from another protocol (interface X) on the router to (interface Y) OSPF, appears ON THE NEXT router as "O E2", but the administrative distance remains the same "AD 110".
Unlike EIGRP - when a router receives a redistributed route from another protocol (in this case RIPv2), it will appear as an EIGRP route with the initials "D EX", but its administrative distance will no longer be 90, in this case it will appear as "AD 170".
In the question we have both, AD 110 (O E2) or AD 170 (D EX) for the same destination network 192.168 1.0. AD 110 will be the winner and will appear in the routing table of router D… AD 170 will be a backup and will only be displayed if the first one fails.
I tried on my virtual environment. The net 192.168.1.0 comes by RIPV2 to Router B with redistribution between routing protocols, it means that 192.168.1.0 go into EIGRP as external route and go in to Router D as D EX with AD 170.
With the knowledge of CCNA which does not include route redistribution the answer should be D
I have read for about an hour and a half about route redistribution between ripv2 & ospf and ripv2 & eigrp on Cisco. And if the redistribution is correctly configured it should also be D.
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