We look for the longest prefix match inclusive of the destination address:
B is incorrect since the destination address falls outside the range of the IP addresses of the network 10.10.13.128/28 (10.10.13.128/28 - 10.10.13.143)
C the default route is only used if there's no route that matches the destination address
D is incorrect it points to a network that doesn't include our destination address
The correct answer is A since it contains the destination address. range (10.10.13.144/28-10.10.13.159/28)
The correct answer is A.
144/28 145-158 (Broadcast 159)
The options below do not cover 10.10.13.158.
128/28 129-142 (Broadcast 143)
160/29 161-166 (Broadcast 167)
208/29 209-214 (Broadcast 215)
10.10.13.144/28 via 10.10.10.9
inc = 16
10.10.13.144(NetAdd) - 10.10.13.159(BroadAdd)
10.10.13.168
10.10.13.145-10.10.13.158 USABLE HOSTS
packet 10.10.130.158 is in range
10.10.13.160/29 via 10.10.10.5
inc = 8
10.10.13.160(NetAdd) - 10.10.13.167(BroadAdd)
10.10.13.168
10.10.13.161-10.10.13.166 USABLE HOSTS
packet 10.10.130.158 is not in range
Answer: A. 10.10.10.9
From:
10.10.13.160/29
Last octet in binary:
10.10.13.10100/000
Address Range:
10.10.13.10100/000 = 10.10.13.160
10.10.13.10100/001 = 10.10.13.161
10.10.13.10100/010 = 10.10.13.162
10.10.13.10100/011 = 10.10.13.163
10.10.13.10100/100 = 10.10.13.164
10.10.13.10100/101 = 10.10.13.165
10.10.13.10100/110 = 10.10.13.166
10.10.13.10100/111 = 10.10.13.167
The subnet "10.10.13.160/29" doesn't contain 10.10.13.158
So, the router cannot find a route for 10.10.13.158 in the route 10.10.13.160/29
So, B is incorrect.
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TechJ
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