An engineer must establish eBGP peering between router R3 and router R4. Both routers should use their loopback interfaces as the BGP router ID. Which configuration set accomplishes this task?
True, because when loopback interfaces used as update source in ebgp, then ebgp-multihop [1-255] command must be used to establish peering between routers besides we're asked to use loopback interfaces as Router IDs.
you are totally correct. BGP would not know how to connect to the peer because the IGP does not know how to get to the peer. (Answer A)
Answer D delivers exactly what was asked for a ROUTER ID or RID.
thanks bro for sharing
Correct answer is D, because the question is asking for use the loopback as the router-id, not forming the adjacency with it. If you need to use the loopback address as the neighbor ip address in BGP you need to add multihop command.
BGP multi-hop is only required if the eBGP peers are more that 1 hop away from each other.
In this segment, they are essentially directly attached, within the same subnet. Multi-hop, in this segment, is not needed.
For loopback-based adjacencies you need 2 things:
1: update-source loopback0 to overwrite the exit interface with the loopback's address
2: a valid route to the peer's loopback on each router so that the router can reach the peer's loopback interface to establish an adjacency.
Answer is D.
Those of you saying 'A'. How? How does 10.3.3.3/32 form a relationship with 10.4.4.4/32? We have no info in this diagram except a known layer 2 link. There is no known static routes linking 10.3.3.3/32 from 10.24.24.3 and vice versa. The solution also suggests we want to use loopback0 as an update-source. The question doesnt ask for this. This eliminates A.
B is not correct because the question states nothing about using loopback as update sources. It's asking for BGP Router ID
C is not correct because we are trying to form a BGP relationship between 2 routers that lack vital routing information. However, the rotuer-id portion is correct...
Which brings us to D.
We are forming a BGP relationship between a layer 2 link between 2 routers, and defining the RID as the loopback0 interface.
Answer A is right .
Bcz by default follow below steps
Use the address configured by the bgp router-id command
Use the Loopback interface address with the highest IP address
Use the highest IP address of the interface
router bgp 100
bgp log-neighbor-changes
no synchronization
neighbor 10.24.24.3 remote-as 200
network 0.0.0.0
Router# sh ip bgp sum
BGP router identifier 10.4.4.4, local AS number 100
BGP table version is 3, main routing table version 6
0 network entries using 0 bytes of memory
0 path entries using 0 bytes of memory
0/0 BGP path/bestpath attribute entries using 0 bytes of memory
0 BGP AS-PATH entries using 0 bytes of memory
0 BGP route-map cache entries using 0 bytes of memory
0 BGP filter-list cache entries using 0 bytes of memory
Bitfield cache entries: current 1 (at peak 1) using 32 bytes of memory
BGP using 32 total bytes of memory
BGP activity 0/0 prefixes, 0/0 paths, scan interval 60 secs
Neighbor V AS MsgRcvd MsgSent TblVer InQ OutQ Up/Down State/PfxRcd
10.24.24.3 4 200 12 14 3 0 0 00:02:02 4
Your post "Neighbor V AS MsgRcvd MsgSent TblVer InQ OutQ Up/Down State/PfxRcd
10.24.24.3 4 200 12 14 3 0 0 00:02:02 4" shows neighborhood failure. Hence "A" is not correct, "D: is the answer.
See here we are forming neighborship with loopback address so BGP going to choose RID by default Loopback address then why do we require to manually configure RID ??
Those of you saying 'A'. How? How does 10.3.3.3/32 form a relationship with 10.4.4.4/32? We have no info in this diagram except a known layer 2 link between another network. There is no known static routes linking 10.3.3.3/32 from 10.24.24.3 and vice versa. Basically, we have no IGP info. The solution also suggests we want to use loopback0 as an update-source. The question doesn't ask for this. This eliminates A.
The question wants you to establish a BGP link between routers. D accomplishes this via the l2 link 1024.24.3 and .4 respectively.
Then the question asks you to use the loopback interface as the BGP router ID. So you set your RID via the bgp router-id command to match that of the loopback.
It's common Cisco word question trickery, i dont expect many people with English as their second language to understand this one.
The answer is D.
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