The answer is wrong. The router can't use the network OSPF because it's another network and not include the destination address (192.168.12.0/28 --> from 192.168.12.0 to 192.168.12.15). The correct answer is D because the RIP route use a /27 subnet and include the destination address (192.168.12.0/27 --> from 192.168.12.0 to 192.168.12.31).
If i wrong please correct me
This completely depends upon if the 192.168.12.16 in the question is a destination network or host address. If it's the destination network then 192.168.12.0/28 is correct since 192.168.12.16 is a network and not a host IP. If 192.168.12.16 is a host IP then the answer is 192.168.12.0/27. In my opinion the question isn't clear but I read it as the destination network.
D is correct. C is wrong since 192.168.12.16 is outside the host address range; therefore, a mask of 255.255.255.224 is able to route traffic properly with RIP /27
And even if they wanted to make this a 'trickier' question, they should have had the last one as 192.168.12.16/28. It would include the address in the range but answer would still be D since .16 would be network address. Basically, a .16 address on a /28 network can never be a host address.
In routing, the prefix length (subnet mask or prefix length in CIDR notation) takes precedence over administrative distance (AD) when determining the best route to a destination network. This concept is known as the "longest prefix match" rule or "most specific route" rule.
C is the answer.For IPv4, the destination address can be a host, network, subnetwork, supernetwork, or default address.
https://www.ibm.com/docs/en/zos/2.4.0?topic=panel-destination-address
D. It selects the RIP route because it has the longest prefix inclusive of the destination address.
I've seen this question somewhere else and the answer they gave for OSPF here wasn't the same, just think they trying to trick people but I hope what I shared can help anyone here new looking for explanation to this question like me.
A router evaluates routes in the following order.
1. Prefix Length - The longest-matching route is preferred first. Prefix length trumps all other route attributes.
2. Administrative Distance - In the event there are multiple routes to a destination with the same prefix length, the route learned by the protocol with the lowest administrative distance is preferred.
3. Metric - In the event there are multiple routes learned by the same protocol with same prefix length, the route with the lowest metric is preferred. (If two or more of these routes have equal metrics, load balancing across them may occur.)
C is the only other "closest" subnet but the broadcast ends at .15 and the next Subnet ID would be .16 which couldn't be used as the first IP address. So D would be correct with an address range from .1-.30
I think the correct answer is A. I believe that when a router is using different routing protocols, the protocol with the lowest administrative distance (EIGRP in this case) is used to route the packet.
EIGRP - 90
RIP - 120
OSPF -110
His assumption is incorrect. administrative distance only come into play when the networks are the same. /24, /27, and /28 are different networks. Thus the network with the closest match will be selected; in this case it is /27 because /28 doesn't include .16 as it is the start of a different network.
This section is not available anymore. Please use the main Exam Page.200-301 Exam Questions
Log in to ExamTopics
Sign in:
Community vote distribution
A (35%)
C (25%)
B (20%)
Other
Most Voted
A voting comment increases the vote count for the chosen answer by one.
Upvoting a comment with a selected answer will also increase the vote count towards that answer by one.
So if you see a comment that you already agree with, you can upvote it instead of posting a new comment.
MM_9
Highly Voted 3 years, 9 months agothegolden3
3 years, 6 months agouevenasdf
3 years, 9 months agoPkard
3 years ago[Removed]
3 years, 2 months agoAli526
Highly Voted 3 years, 9 months agoIxlJustinlxl
3 years, 5 months agodaddydagoth
1 year, 8 months agoeb63e5a
Most Recent 6 months ago[Removed]
7 months, 1 week agoshumps
1 year, 2 months agobinrayelias
1 year, 9 months agobinrayelias
1 year, 9 months agoatika870
1 year, 10 months ago[Removed]
2 years ago[Removed]
2 years, 1 month agoZUMY
2 years, 3 months agoDARKK
2 years, 5 months agodave1992
2 years, 10 months agoAnarckii
2 years, 10 months agoshakyak
2 years, 11 months agokokoyul
3 years, 1 month agoAdekoya_Oluwatobi
3 years, 1 month agoRougePotatoe
2 years agoilluded03jolted
2 years, 4 months agoChenet
3 years, 1 month agoPamirt
3 years, 2 months ago