correct answer is A&D
A. The command "ip route 172.16.3.0 255.255.255.0 192.168.2.4" establishes a static route to the 172.16.3.0 network. This means that the router knows how to reach the devices in the 172.16.3.0 network, and it will use the interface with the address 192.168.2.4 to reach them.
D. The command "ip route 172.16.3.0 255.255.255.0 192.168.2.4" also configures the router to send any traffic for an unknown destination out the interface with the address 192.168.2.4. This is because it's a default route (also known as the gateway of last resort), which means if the router doesn't have a specific route for a destination, it will send the traffic out through this interface.
The other options (B, C, E, and F) do not accurately describe the behavior of the given command.
ip route command has the following order: (destination IP) (mask) (next hop) (AD)
as the AD is not specified in the question, I asume that is using its default AD, so answer E is correct.
so does the inverse applies here as well. Could i reverse the cmd and yield the same result
if
ip route 192.168.2.4 255.255.255.0 172.16.3.0
Will destination be to the 172.16.3.0 network from 192.168.2.4?
as first, as ip route you need to follow network rules, so it's not 192.168.2.4 but it is 192.168.2.0. As second, if you invert it, it means that you'll reach 192.168.2.4 through 172.16.3.0
The command for static routes are “ip route (destination) (subnet mask) (next hop)” making 3.0 the destination network (A). E also is correct because the question did not add a custom administrative distance making it the default of 1.
A. It establishes a static route to the 172.16.3.0 network.
Correct answer.
B. It establishes a static route to the 192.168.2.0 network.
Wrong answer.
C. It configures the router to send any traffic for an unknown destination to the 172.16.3.0 network.
Wrong answer.
D. It configures the router to send any traffic for an unknown destination out the interface with the address 192.168.2.4.
Wrong answer.
E. It uses the default administrative distance.
Correct answer.
F. It is a route that would be used last if other routes to the same destination exist.
Wrong answer.
Router(config)#int f1/0
Router(config-if)#ip ad
Router(config-if)#ip address 192.168.2.1 255.255.255.0
Router(config-if)#no sh
Router(config-if)#no shutdown
Router(config-if)#
%LINK-5-CHANGED: Interface FastEthernet1/0, changed state to up
Router(config-if)#
Router(config-if)#int f2/0
Router(config-if)#ip ad
Router(config-if)#ip address 192.168.2.2 255.255.255.0
% 192.168.2.0 overlaps with FastEthernet1/0
A is correct because "ip route" works with the format "destination-address mask [ exit-interface | next-hop-address ].
B is correct because it doesn't explicitly specify an administrative distance at the end of the command, so it uses the default AD of 1.
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