An engineer must configure HSRP for VLAN 1200 on SW1. The second switch is configured by using the last usable IP address in the network as the virtual IP. Which command set accomplishes this task?
A.
SW1(config)# interface vlan 1200 SW1(config-if)# ip address 172.12.0.254 255.255.255.0 SW1(config-if)# standby version 2 SW1(config-if)# standby 1200 ip 172.12.0.2 SW1(conflg-it)# standby 1200 preempt
B.
SW1(config)# interface vlan 1200 SW1(config-if)# ip address 172.12.0.2 255.255.255.0 SW1(config-if)# standby version 2 SW1(config-if)# standby 1200 ip 172.12.0.254 SW1(conflg-it)# standby 1200 preempt
C.
SW1(config)# interface vlan 1200 SW1(config-if)# ip address 172.12.0.2 255.255.255.0 SW1(config-if)# standby 1200 ip 172.12.0.254 SW1(config-if)# standby 1200 timers 5 15 SW1(conflg-it)# standby 1200 preempt
D.
SW1(config)# interface vlan 1200 SW1(config-if)# ip address 172.12.0.1 255.255.255.0 SW1(config-if)# standby 1200 ip 172.12.0.254 SW1(config-if)# standby 1200 timers 5 15 SW1(conflg-it)# standby 1200 preempt
because we use the group number 1200 , we must configure HSRP version 2 , if we dont do that , we receive this error :
Switch(config-if)#standby 1200 ip 172.12.0.254
PT ERROR: HSRP version 2 is required for specified group number
-- so the option C and D is wrong
-- and A is wrong because he doesn't use last usable IP address for virtual IP
The standby group number= The default is 0. The group number range is from 0 to 255 for HSRP version 1 and from 0 to 4095 for HSRP version 2.
need to specify "standby version 2" in order to assign group number 1200
HSRP group number is greater than 255, version 2 must be used.
The virtual IP address is configured to be the last usable IP in the subnet (172.12.0.0/24) = 172.12.0.254/24
B is correct
no need for timers or preemption
stick to the question, you were asked to just configure HSRP with a virtual IP "the last available in the subnet" so find the option with the correct addressing and the fewer extra configuration
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