1)PC1 tries to ping PC3 for the first time.
2)sends out an ARP to S1.
If SW1 were to have an entry for PC3 in it's table, PC1 would not have had sent an arp request, that means that SW1 has no entry for PC3, so it will be flooded out of every port, answer is A.
What does PC1's cache have to do with the switch1's ARP table?
The switch does not constantly send information to PCs about the information it stores in its ARP table.
A PC only stores information in its cache when it sends an ARP request and receives a response. Therefore PC1 has no idea if the Switch has information in its ARP table about PC3 or not.
Please don't confuse
it says ARP request. ARP works at Network Layer and is not handled by switch, instead the switch forwards the frame containing ARP request to the default Gateway which is probably living in the router.
ARP is L2 protocol, and it's handled by the switch.
The switch floods ARP request through all other ports.
Default Gateway is not "living in the router", does not receive frames (L2) but packets (L3) which has nothing to do with this situation.
Very weird question, but it made me wonder some interesting questions.
Please, correct me if im wrong.
- Is S1's ARP table supposed to be empty? If so, answer A would be correct, but it does not indicate that the ARP table is empty. The statement says that PC1 tries to ping PC3 for the first time, but we do not know if S1 already knows PC1's MAC because it has previously sent traffic to other devices, nor do we know if S1 has information from PC3 for the same reason.
- Are the PCs supposed to be on different VLANs? It is assumed that it is, but it is not specified.
- It is assumed that if they are not on the same VLAN, it is a "Router on a Stick so:
In theory, if the PCs are not in the same VLAN, PC1 would directly send the frame to the default gateway on Router, because PC1 knows that PC3 is not in the same VLAN by looking at its own network mask.
In any case, the key would be to know if S1's ARP table is empty or not. Information is clearly missing from the question.
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