Refer to the exhibit. An engineer configures router B to direct all traffic from host 192.168.1.3 to router C. All other traffic must be routed through normal routing-protocol operations. Which configuration accomplishes the task?
A.
interface g0/0/0 ip address 192.168.1.254 255.255.255.0 ! access-list 101 permit ip host 192.168.1.3 any access-list 101 permit ip any any ! route-map CCNP permit 10 match ip address 101 set ip next-hop 10.0.1.2
B.
interface g0/0/0 ip address 192.168.1.254 255.255.255.0 ip policy route-map CCNP ! access-list 101 permit ip host 192.168.1.3 any ! route-map CCNP permit 10 match ip address 101 set ip next-hop 10.0.2.1
C.
interface g0/0/0 ip address 192.168.1.254 255.255.255.0 ip policy route-map CCNP ! access-list 101 permit ip any host 192.168.1.3 ! route-map CCNP permit 10 match ip address 101 set ip next-hop 10.0.1.2
D.
interface g0/0/0 ip address 192.168.1.254 255.255.255.0 ip policy route-map CCNP ! access-list 101 permit ip host 192.168.1.3 any ! route-map CCNP permit 10 match ip address 101 set ip next-hop 10.0.1.2
A: missing the ip policy route-map CCNP under int Gi0/0
B: wrong next-hop (10.0.2.1 instead of 10.0.1.2)
C: the direction is opposite in access-list 101
D: correct
Well, next-hop in answer B also point to router C. Not clear the route redistribution of 192.168.1.0/24 prefix (to EIGRP or to OSPF ASBR) So answer B possible solution too.
The any any statement in the ACL will make all traffic route via 10.0.1.2 rather than just traffic sourced from 192.168.1.3
upvoted 5 times
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