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Exam AWS Certified Developer Associate topic 1 question 55 discussion

Exam question from Amazon's AWS Certified Developer Associate
Question #: 55
Topic #: 1
[All AWS Certified Developer Associate Questions]

A Developer must build an application that uses Amazon DynamoDB. The requirements state that the items being stored in the DynamoDB table will be 7KB in size and that reads must be strongly consistent. The maximum read rate is 3 items per second, and the maximum write rate is 10 items per second.
How should the Developer size the DynamoDB table to meet these requirements?

  • A. Read: 3 read capacity units Write: 70 write capacity units
  • B. Read: 6 read capacity units Write: 70 write capacity units
  • C. Read: 6 read capacity units Write: 10 write capacity units
  • D. Read: 3 read capacity units Write: 10 write capacity units
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Suggested Answer: B 🗳️

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FHU
Highly Voted 3 years, 6 months ago
(B) is correct. We are talking about 3 strong reads of 7KB. 7KB requires 2 RCUs, so 3 x 2 = 6. Regarding the writes, we are talking about 10 itens per second. 7KB requires 7 WCUs. So 10 x 7 = 70.
upvoted 40 times
Goss
3 years, 4 months ago
Tip: One RCU takes 4KB/s and One WCU takes 1KB/s, so for this question 3 req * 2RCU = 6; 10 req* 7WCU = 70WCU. In case, if 512 bytes/sec is mentioned (like how many WCU's are needed for 10 items with 512bytes?), "round off" results to 1KB and 1WCU is needed for it (answer: 10WCU and not 5WCU).
upvoted 8 times
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sg0206
Highly Voted 3 years, 7 months ago
B is correct
upvoted 14 times
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sumanshu
Most Recent 4 months, 1 week ago
Selected Answer: B
B) Correct - Total Read Size 3*7 = 21 KB -- 4 KB by 1 RCU. 21 by approx 6 Total Write Size 70 KB --- 1 WCU per 1 KB = 70 WCU
upvoted 1 times
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rcaliandro
1 year, 10 months ago
Selected Answer: B
B is the correct one because: - WCU = 10/1 * 7 ====> 70 - RCU (strongly consistent) = 3/4 * 7 = 5.25 ==> 6
upvoted 2 times
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sichilam
2 years, 3 months ago
B is correct
upvoted 1 times
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GenePoole
2 years, 7 months ago
Selected Answer: B
strongly consistent = 1 RCU per 4k, so 2 RCU per read and we have 3 per second, so 2x3=6 read capacity. Write uses 1k as its capacity, so 7k items will take 7 WCU, as we have 10 writes per second 10x7 = 70.
upvoted 1 times
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VijiTu
2 years, 10 months ago
How is DynamoDB RCU calculated? 1 read capacity unit (RCU) = 1 strongly consistent read of up to 4 KB/s = 2 eventually consistent reads of up to 4 KB/s per read. 2 RCUs = 1 transactional read request (one read per second) for items up to 4 KB. For reads on items greater than 4 KB, total number of reads required = (total item size / 4 KB) rounded up. DynamoDB charges one WCU for each write per second (up to 1 KB) and two WCUs for each transactional write per second. This should help with calculations. Here we have strong read consistency. Its 1 RCU upto 4Kb. In our case its 7 Kb so we need 2 RCU. For write we need 7 WCU. Here as per the query its 3 reads/second so 3*2=6 and for writes 7*10=70
upvoted 3 times
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ShrikantMS
3 years, 2 months ago
B 1 : Strong Read=4KB 7/4=1.7=2*3=6 2 : Write 7KB *10=70
upvoted 3 times
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leliodesouza
3 years, 4 months ago
Selected Answer: B
Answer: B
upvoted 2 times
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VAG1595
3 years, 5 months ago
Answer: B
upvoted 2 times
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wils3
3 years, 5 months ago
Ans: B
upvoted 2 times
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vjt
3 years, 6 months ago
It is B.
upvoted 2 times
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Chinta
3 years, 6 months ago
B is the correct answer .RCU=3*(7KB/4)=6 ,WCU=10*7KB=70
upvoted 2 times
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Ayusef
3 years, 6 months ago
B... it correct see FHU answer.
upvoted 1 times
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saeidp
3 years, 6 months ago
B is correct
upvoted 1 times
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ipindado2020
3 years, 6 months ago
I go for B... RCU: 3 * 8 = 24.....24/4 = 6 WCU: 7 * 10 => 70
upvoted 1 times
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onlinebaba
3 years, 6 months ago
B item size 7kb to read each item with strong consisency we need 2 RCU to write each item we need 7 WCU max read rate = 3 items/sec which is 3*7 = 21kb in total and requires 6 RCU max write rate = 10 items/sec which is 10*7 70 kb in total and requires 70 RCU
upvoted 4 times
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